(2^2x)(2^6)=2^-x/3

Solution for (2^2x)(2^6)=2^-x/3 equation:

(2^2x)(2^6)=2^-x/3

We move all terms to the left:

(2^2x)(2^6)-(2^-x/3)=0

We get rid of parentheses

2^2x2^6+x/3-2^=0

We multiply all the terms by the denominator


2^2x2^6*3+x-2^*3=0

We add all the numbers together, and all the variables

x+2^2x2^6*3=0

Wy multiply elements

6x^2+x=0

a = 6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·6·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*6}=\frac{-2}{12}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*6}=\frac{0}{12}
=0
$